Correct option is D
Given:
Word = COVID
Number of letters = 5
All letters are distinct
Formula Used:
Number of arrangements of n distinct letters = n! (n factorial)
Solution:
Since all 5 letters in the word COVID are different:
Total number of possible words = 5! = 5 × 4 × 3 × 2 × 1 = 120
Ans. (d) 120