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Heating of ethanol at 443 K with excess concentrated sulphuric acid yields which of the following?
Question

Heating of ethanol at 443 K with excess concentrated sulphuric acid yields which of the following?

A.

Ethane

B.

Acetic acid

C.

Ether

D.

Ethene

Correct option is D

The Correct Answer is: (d) Ethene
Explanation:
When ethanol (C₂H₅OH) is heated at 443 K in the presence of excess concentrated sulphuric acid (H₂SO₄), it undergoes dehydration (removal of water) to form ethene (C₂H₄), an unsaturated hydrocarbon (alkene).
Reaction:

C2H5OH443 Kconc. H2SO4C2H4+H2OC_2H_5OH \xrightarrow[443\,K]{conc.\,H_2SO_4} C_2H_4 + H_2O​​
This is an elimination reaction, where a water molecule is removed from ethanol.

Information Booster:

• This reaction is an example of acid-catalyzed dehydration of alcohol.
• Ethene formed is a colourless and flammable gas, used in the manufacture of plastics like polythene.
• Concentrated H₂SO₄ removes water, favoring formation of unsaturated hydrocarbons.​

Additional Information:
  •  Ethane – Ethane (C₂H₆) is formed by hydrogenation.
  • Acetic acid – Acetic acid (CH₃COOH) is formed by oxidation of ethanol.
  • Ether – Ether is formed when ethanol reacts with another ethanol molecule under specific conditions.

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