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​Glycolysis and citric acid cycle contribute precursors to many biosynthetic pathways in plants. Column X lists names of the precursor and column Y li
Question

Glycolysis and citric acid cycle contribute precursors to many biosynthetic pathways in plants. Column X lists names of the precursor and column Y lists the product synthesized.

Which one of the following options represents the correct match between column X and Y?

A.

A - ii, B - iii, C - i, D - iv

B.

A - iii, B - ii, C - iv, D - i

C.

A - iv, B - i, C - iii, D - ii

D.

A - i, B - ii, C - iii, D - iv

Correct option is B

Explanation-

A. Hexose phosphate → (iii) Cellulose
Hexose phosphate refers to phosphorylated six-carbon sugars, such as:
                                                            1.    Glucose-6-phosphate
                                                            2.    Fructose-6-phosphate
These are central to carbohydrate metabolism. In plants, glucose-6-phosphate is used to form UDP-glucose, a key precursor for Cellulose (a structural polysaccharide in plant cell walls) and  Starch.
​So, Hexose phosphate is the direct precursor of Cellulose.

B. Pyruvate → (ii) Alanine

Pyruvate is the end product of glycolysis. It serves as a starting point for TCA cycle (aerobic respiration) and Amino acid biosynthesis. Through transamination, pyruvate is converted into Alanine (a non-essential amino acid)
 The reaction:
                   Pyruvate + Glutamate → Alanine + α-ketoglutarate
                      (Enzyme: alanine aminotransferase)
So, Pyruvate is a direct precursor of Alanine.

C. Pentose phosphate → (iv) Nucleotides
The Pentose Phosphate Pathway (PPP) branches off glycolysis and produces NADPH (for biosynthesis) , Ribose-5-phosphate.
Ribose-5-phosphate is a pentose sugar and is the sugar backbone of RNA (ribose) and DNA (deoxyribose). It's used in synthesizing Purines and Pyrimidines and nucleotides like ATP, GTP, etc.
So, Pentose phosphate is a key precursor for Nucleotide biosynthesis.

D. Oxaloacetate → (i) Aspartate
Oxaloacetate (OAA) is a 4-carbon intermediate of the TCA cycle. Through transamination, OAA is converted into Aspartate (a key amino acid).
The reaction:
OAA + Glutamate → Aspartate + α-ketoglutarate
   (Enzyme: aspartate aminotransferase)
Aspartate is also a precursor for other amino acids (e.g., lysine, threonine) and nucleotide synthesis (purine and pyrimidine rings)

So, the correct answer is b - ​A - iii, B - ii, C - iv, D - i

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