Four triads of numbers have been given out of which three are alike in some manner and one is different. Select the one that is different.

Logic: Middle = (First − 2) × First + 3

Third = (First − 1)³ + 3

A: 9-29-259
Middle → (9−2)×9+3 = 7×9+3 = 66 ≠ 29 ✘

B: 6-27-128
Middle → (6−2)×6+3 = 4×6+3 = 27 
Third → (6−1)³+3 = 5³+3 = 125+3 = 128 

C: 5-18-67
Middle → (5−2)×5+3 = 3×5+3 = 18 
Third → (5−1)³+3 = 4³+3 = 64+3 = 67 

D: 7-38-219
Middle → (7−2)×7+3 = 5×7+3 = 38 
Third → (7−1)³+3 = 6³+3 = 216+3 = 219 

Thus B, C, D follow the rule but A does not.

Final Answer:
9 – 29 – 259

Final Correct Option:
(A)