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    For what values of 'k' does the equation kx(x-2)+6=0 have equal roots?
    Question

    For what values of 'k' does the equation kx(x-2)+6=0 have equal roots?

    A.

    6

    B.

    -2

    C.

    3, 2

    D.

    0, 6

    Correct option is A

    kx(x-2)+ 6 = 0
    kx2 - 2kx+6= 0
    Since, roots of this equation are equal, then b2 = 4ac
    (-2k)2 = 4 ×k ×6
    K2 = 6k
    =>k2-6k = 0
    =>k(k - 6) = 0
    k = 0 and 6
    Case 1: For k=0, roots are undefined
    Case 2: For k= 6, both roots are unity

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