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    For a book of mass m, moving a distance d on a smooth horizontal table, the work done due to gravitational force is:
    Question

    For a book of mass m, moving a distance d on a smooth horizontal table, the work done due to gravitational force is:

    A.

    md

    B.

    mgd

    C.

    0

    D.

    md cosθ\theta​​

    Correct option is C

    ​The correct answer is (c) 0

    Explanation:

    Work done by a force is given by the formula:

             W=FdcosθW = F \cdot d \cdot \cos \theta​​

    where:

    • W = Work done
    • F = Force applied
    • d = Displacement
    • θ\theta​ = Angle between force and displacement

    In this case:

    • The gravitational force acts vertically downward (towards the center of the Earth).
    • The displacement of the book is horizontal along the table.
    • The angle θ\theta ​between the gravitational force and displacement is 90°.
    • Since cos90=0cos 90^\circ = 0​, the work done by the gravitational force is:

                                           W=mgdcos90=mgd×0=0W = mg \cdot d \cdot \cos 90^\circ = mgd \times 0 = 0​​

    Thus, the work done by gravity is zero, as gravity does not contribute to the horizontal motion of the book.

    Information Booster:

    • Positive work: When force and displacement are in the same direction (e.g., lifting an object upward).
    • Negative work: When force and displacement are in opposite directions (e.g., friction opposing motion).
    • Zero work: When force is perpendicular to displacement or when no displacement occurs (e.g., carrying a bag horizontally while gravity acts vertically).

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