Five capacitors, each one having the value of 10 µF, are connected in series. The equivalent capacitance of the series connection is_______

Correct option is C

​$$\begin{aligned}&\text{When capacitors are connected in series, the equivalent capacitance } C_{\text{eq}} \text{ is given by:} \\&\frac{1}{C_{\text{eq}}} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3} + \cdots + \frac{1}{C_n} \\\\&\text{Since all five capacitors have the same value of } 10\,\mu\text{F}, \text{ we can simplify this formula as:} \\&\frac{1}{C_{\text{eq}}} = \frac{1}{10} + \frac{1}{10} + \frac{1}{10} + \frac{1}{10} + \frac{1}{10} \\&\frac{1}{C_{\text{eq}}} = \frac{5}{10} = \frac{1}{2} \\\\&\text{Now, take the reciprocal to find } C_{\text{eq}}: \\&C_{\text{eq}} = 2\,\mu\text{F}\end{aligned}$$​​