​Find the value of the expression given below, correct upto 2 decimal places.​

​$$\frac{(0.96)^3 - (0.1)^3}{(0.96)^2 + 0.096 + (0.1)^2}$$​​

Correct option is C

Given:

$$\frac{(0.96)^3 - (0.1)^3}{(0.96)^2 + 0.096 + (0.1)^2}$$

Solution:

$$\text{Use identity: } \frac{a^3 - b^3}{a^2 + ab + b^2} = a - b\\\ \\\text{Let } a = 0.96, \quad b = 0.1\\\ \\\Rightarrow \frac{(0.96)^3 - (0.1)^3}{(0.96)^2 + (0.96)(0.1) + (0.1)^2} \\\ \\= 0.96 - 0.1 = 0.86\\\ \\\text{Final Answer: } \boxed{0.86}$$​