Find the value of the expression $$\frac{0.079^2 + 0.25^2 + 3.37^2}{0.0079^2 + 0.025^2 + 0.337^2}$$​​

Correct option is C

Given:
Expression: $$\frac{0.079^2 + 0.25^2 + 3.37^2}{0.0079^2 + 0.025^2 + 0.337^2}$$​​
Formula Used:
​$$(\frac{x}{10})^2 = \frac{x^2}{100}$$​​
Solution:
Observe the decimal relationship between the numerator and denominator terms:
0.0079 = $$\frac{0.079}{10}$$​​

0.025 = $$\frac{0.25}{10}$$​

0.337 = $$\frac{3.37}{10}$$​​
Substitute these fractional equivalents into the denominator:
Denominator = $$(\frac{0.079}{10})^2 + (\frac{0.25}{10})^2 + (\frac{3.37}{10})^2$$​​
Factor out the common multiplier:
Denominator = $$\frac{1}{100} × (0.079^2 + 0.25^2 + 3.37^2)$$​​
Now, substitute the simplified denominator back into the original expression:
​$$\frac{0.079^2 + 0.25^2 + 3.37^2}{\frac{1}{100} × (0.079^2 + 0.25^2 + 3.37^2)}$$​​
Cancel the identical bracketed terms in the numerator and denominator:
​$$\frac{1}{\frac{1}{100}} = 100$$​​
Final Answer
So the correct answer is (c)