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    Find the value of sin⁡(180∘+θ)sec⁡(360∘−θ)cot⁡(90∘−θ)tan⁡(180∘+θ)sec⁡(−θ)cos⁡(90∘+θ)\frac{\sin \left(180^{\circ}+\theta\right) \sec \left(360^{\circ}-
    Question

    Find the value of sin(180+θ)sec(360θ)cot(90θ)tan(180+θ)sec(θ)cos(90+θ)\frac{\sin \left(180^{\circ}+\theta\right) \sec \left(360^{\circ}-\theta\right) \cot \left(90^{\circ}-\theta\right)}{\tan \left(180^{\circ}+\theta\right) \sec (-\theta) \cos \left(90^{\circ}+\theta\right)}​.

    A.

    0

    B.

    1

    C.

    tan(θ)

    D.

    sin(θ)

    Correct option is B

    sin(180+θ)sec(360θ)cot(90θ)tan(180+θ)sec(θ)cos(90+θ)=(sinθ)(secθ)(tanθ)(tanθ)(secθ)(sinθ)=1\frac{\sin(180^\circ + \theta) \sec(360^\circ - \theta) \cot(90^\circ - \theta)}{\tan(180^\circ + \theta) \sec(-\theta) \cos(90^\circ + \theta)} = \frac{(-\sin \theta)(\sec \theta)(\tan \theta)}{(\tan \theta)(\sec \theta)(-\sin \theta)} = 1​​

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