Find the value of:  $$9^3 - 2^2 + \left( \frac{42}{3} \right)^2 - 6 + 5 \times 0$$​​

Correct option is A

Given:

​$$9^3 - 2^2 + \left( \frac{42}{3} \right)^2 - 6 + 5 \times 0$$​​

Concept Used:

Solution:

$$9^3 - 2^2 + \left( \frac{42}{3} \right)^2 - 6 + 5 \times 0 \\ \ \\ =729 -4+196-6 \\ \ \\ =729 +196 -10 \\ \ \\ = 729+186 \\ \ \\ =915$$​​