Find the value of $$\left[(90 ÷ 3) × \left\{\frac{63}7+\frac{28}3 × (8 - 3)\right\}\right]$$​​

Correct option is D

Given: ​

​$$\left[(90 ÷ 3) × \left\{\frac{63}7+\frac{28}3 × (8 - 3)\right\}\right]$$ 

Concept Used: ​

Solution: ​

​$$\left[(90 ÷ 3) × \left\{\frac{63}7+\frac{28}3 × (8 - 3)\right\}\right] \\ \ \\ = \left[(30) × \left\{9+\frac{28}3 × (5)\right\}\right] \\ \ \\ = \left[(30) × \left\{9 + \frac{140}3 \right\}\right] \\ \ \\ = \left[(30) × \left\{ \frac{27+140}3 \right\}\right]\\ \ \\ = \left[(30) × \left\{ \frac{167}3 \right\}\right] \\ \ \\ = \left[10 ×167\right] \\ \ \\ = 1670$$​​