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    Find the value of (82+28)2−(82−28)282×28\frac{(82 + 28)^2 - (82 - 28)^2}{82 \times 28}82×28(82+28)2−(82−28)2​​​
    Question

    Find the value of (82+28)2(8228)282×28\frac{(82 + 28)^2 - (82 - 28)^2}{82 \times 28}​​

    A.

    8

    B.

    110

    C.

    4

    D.

    220

    Correct option is C

    Given:

    (82+28)2(8228)282×28\frac{(82 + 28)^2 - (82 - 28)^2}{82 \times 28}​​

    Formula Used:

    (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2  

    (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2​  

    Solution:

    (82+28)2(8228)282×28\frac{(82 + 28)^2 - (82 - 28)^2}{82 \times 28} 

    ((82+28)(8228))((82+28)+(8228))84×28\frac{\left((82 + 28) - (82 - 28)\right)\left((82 + 28) + (82 - 28)\right)}{84\times28} 

    =56×16482×28 \frac{56 \times 164}{82 \times 28} 

    =4 

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