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Find the value of [(81÷3)×{408+342×(9−7)}][(81 \div 3) \times \{\frac{40}{8} + \frac{34}{2} \times (9 - 7)\}][(81÷3)×{840​+234​×(9−7)}]​​
Question

Find the value of [(81÷3)×{408+342×(97)}][(81 \div 3) \times \{\frac{40}{8} + \frac{34}{2} \times (9 - 7)\}]​​

A.

1071

B.

1053

C.

1037

D.

1067

Correct option is B

Given:

[(81÷3)×{408+342×(97)}][(81 \div 3) \times \{\frac{40}{8} + \frac{34}{2} \times (9 - 7)\}]​​

Formula Used:

Operation preference wiseSymbolBrackets[],,()Orders,of²(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin {array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}

Solution:

[(81÷3)×{408+342×(97)}][(81 \div 3) \times \{\frac{40}{8} + \frac{34}{2} \times (9 - 7)\}]​​

[(27)×{5+17×(2)}][(27) \times \{5 + 17 \times (2)\}]​​

[27×{5+34}][27 \times \{5 + 34\}]​​

[27×39][27 \times 39] 

= 1053

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