arrow
arrow
arrow
Find the value of (63÷9)×{968+114×(9−5)}\left(63 \div 9\right) \times \left\{ \frac{96}{8} + \frac{11}{4} \times (9 - 5) \right\}(63÷9)×{896​+411
Question

Find the value of (63÷9)×{968+114×(95)}\left(63 \div 9\right) \times \left\{ \frac{96}{8} + \frac{11}{4} \times (9 - 5) \right\}​​

A.

153

B.

165

C.

161

D.

169

Correct option is C

Given:
(63÷9)×{968+114×(95)}\left(63 \div 9\right) \times \left\{ \frac{96}{8} + \frac{11}{4} \times (9 - 5) \right\} 

Concept Used:
Operation preference wiseSymbolBrackets[],,()Orders,of²(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}

Solution:

(63÷9)×{968+114×(95)}=7×{12+114×4}=7×{12+11}=7×23=161\left(63 \div 9\right) \times \left\{ \frac{96}{8} + \frac{11}{4} \times (9 - 5) \right\}\\= 7 \times \left\{ 12 + \frac{11}{4} \times 4 \right\}\\= 7 \times \left\{ 12 + 11\right\} \\= 7 \times 23\\ = 161

Free Tests

Free
Must Attempt

SSC GD PYP (Held on 4 Feb 2025 S1)

languageIcon English
  • pdpQsnIcon80 Questions
  • pdpsheetsIcon160 Marks
  • timerIcon60 Mins
languageIcon English
Free
Must Attempt

Hindi Section Test 1

languageIcon English
  • pdpQsnIcon20 Questions
  • pdpsheetsIcon40 Marks
  • timerIcon12 Mins
languageIcon English
Free
Must Attempt

SSC GD Constable Full Mock Test 1

languageIcon English
  • pdpQsnIcon80 Questions
  • pdpsheetsIcon160 Marks
  • timerIcon60 Mins
languageIcon English
test-prime-package

Access ‘SSC GD’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
354k+ students have already unlocked exclusive benefits with Test Prime!
Our Plans
Monthsup-arrow