Find the value of $$36-2(20+12÷4×3-2×2)+10$$​.

Correct option is A

Given:​

​$$36-2(20+12÷4×3-2×2)+10$$

Concept Used:​

​$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline\text{Brackets} &[],{}, () \\ \hline \text{Orders, of} & ^x(power), √ (root) , of \\ \hline \text{Division}& ÷ \\\hline \text{Multiplication} & × \\ \hline \text{Addition} & + \\ \hline \text{Subtraction} & - \\\hline\end{array}$$

Solution:​

​$$36-2(20+12÷4×3-2×2)+10$$

=$$36-2(20+3×3-2×2)+10$$

=$$36-2(20+9-4)+10$$

=$$36-2(29-4)+10$$

=$$36-2(25)+10$$

= 36 - 50 + 10

= 46 - 50 = - 4