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    Find the value of [(27×11)×{8÷8×(19−15)4})[(27 \times 11) \times \{8 \div 8 \times \frac{(19 - 15)}{4}\})[(27×11)×{8÷8×4(19−15)​})​​
    Question

    Find the value of [(27×11)×{8÷8×(1915)4})[(27 \times 11) \times \{8 \div 8 \times \frac{(19 - 15)}{4}\})​​

    A.

    282

    B.

    309

    C.

    289

    D.

    297

    Correct option is D

    Given:

    [(27×11)×{8÷8×(1915)4})[(27 \times 11) \times \{8 \div 8 \times \frac{(19 - 15)}{4}\})

    Concept Used:

    Operation preference wiseSymbolBrackets[],,()Orders, ofx(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline\text{Brackets} &[],{}, () \\ \hline \text{Orders, of} & ^x(power), √ (root) , of \\ \hline \text{Division}& ÷ \\\hline \text{Multiplication} & × \\ \hline \text{Addition} & + \\ \hline \text{Subtraction} & - \\\hline\end{array}

    Solution:

    [(27×11)×{8÷8×(1915)4})[(27 \times 11) \times \{8 \div 8 \times \frac{(19 - 15)}{4}\})

    =[(27×11)×{1×44})[(27 \times 11) \times \{1 \times \frac{4}{4}\})

    =[(27×11)×{1×1})[(27 \times 11) \times \{1 \times 1\})

    =297

    Option (d) is right.

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