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    Find the value of 23−(−13)+(−229)\frac{2}{3} - \left(-\frac{1}{3}\right) + \left(-2\frac{2}{9}\right)32​−(−31​)+(−292​)​​
    Question

    Find the value of 23(13)+(229)\frac{2}{3} - \left(-\frac{1}{3}\right) + \left(-2\frac{2}{9}\right)​​

    A.

    11/9

    B.

    - 11/9

    C.

    17/9

    D.

    - 17/9

    Correct option is B

    We are given the expression:

    23−(−13)+(−229)\frac{2}{3} - \left(-\frac{1}{3}\right) + \left(-2\frac{2}{9}\right)32(31)+(292)

    Step 1: Simplify the terms

    • First term: 23\frac{2}{3}​​

    • Second term: 

      (13)=+13-(-\frac{1}{3}) = +\frac{1}{3}​​

    • Third term: −229=−(2+29)=−209-2\frac{2}{9} = -\left(2 + \frac{2}{9}\right) = -\frac{20}{9}292=(2+92)=920

    Step 2: Add the first two terms

    23+13=33=1\frac{2}{3} + \frac{1}{3} = \frac{3}{3} = 132+31=33=1

    Step 3: Now subtract the third term

    209=99209=119 - \frac{20}{9} = \frac{9}{9} - \frac{20}{9} = \frac{-11}{9}

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