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Find the value of 23−(−13)+(−229)\frac{2}{3} - \left(-\frac{1}{3}\right) + \left(-2\frac{2}{9}\right)32​−(−31​)+(−292​)​​
Question

Find the value of 23(13)+(229)\frac{2}{3} - \left(-\frac{1}{3}\right) + \left(-2\frac{2}{9}\right)​​

A.

11/9

B.

- 11/9

C.

17/9

D.

- 17/9

Correct option is B

We are given the expression:

23−(−13)+(−229)\frac{2}{3} - \left(-\frac{1}{3}\right) + \left(-2\frac{2}{9}\right)32(31)+(292)

Step 1: Simplify the terms

  • First term: 23\frac{2}{3}​​

  • Second term: 

    (13)=+13-(-\frac{1}{3}) = +\frac{1}{3}​​

  • Third term: −229=−(2+29)=−209-2\frac{2}{9} = -\left(2 + \frac{2}{9}\right) = -\frac{20}{9}292=(2+92)=920

Step 2: Add the first two terms

23+13=33=1\frac{2}{3} + \frac{1}{3} = \frac{3}{3} = 132+31=33=1

Step 3: Now subtract the third term

209=99209=119 - \frac{20}{9} = \frac{9}{9} - \frac{20}{9} = \frac{-11}{9}

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