Find the value of $$\left(14\div2\right) \times \left\{ \frac{14}{7} + \frac{40}{3} \times (7 - 4) \right\}$$​​

Correct option is D

Given:
​$$\left(14\div2\right) \times \left\{ \frac{14}{7} + \frac{40}{3} \times (7 - 4) \right\}$$​​
Concept Used:
​$$\begin {array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}$$   

Solution:
$$\left(14\div2\right) \times \left\{ \frac{14}{7} + \frac{40}{3} \times (7 - 4) \right\} \\= 7\times \left\{ 2 + \frac{40}{3} \times 3 \right\} \\ = 7\times { 2 +40}\\= 7 \times 42 \\= 294\\$$

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