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Find the slope of the line which is perpendicular to the line connecting the points A(- 5, 3) and B(2, 6)
Question

Find the slope of the line which is perpendicular to the line connecting the points A(- 5, 3) and B(2, 6)

A.

49\frac{4}{9}

B.

35\frac{3}{5}​​

C.

87\frac{-8}{7}

D.

73\frac{-7}{3}

Correct option is D

Step 1: Find the slope of the line connecting points A and B

The formula for the slope m between two points x1,y1x_1, y_1​ and x2,y2x_2, y_2​ is:
m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}
Substitute (x1,y1)(x_1, y_1)​ = (-5, 3) and (x2,y2)(x_2, y_2)​ = (2, 6):
m=632(5)=37m = \frac{6 - 3}{2 - (-5)} = \frac{3}{7}

Step 2: Find the slope of the perpendicular line.
The slope of a line perpendicular to another is the negative reciprocal of the original slope. If the slope of the original line is m, the slope of the perpendicular line is:
mperpendicular=1mm_\text{perpendicular} = -\frac{1}{m}

Substitute m=37m = \frac{3}{7}
mperpendicular=137=73m_\text{perpendicular} = -\frac{1}{\frac{3}{7}} = -\frac{7}{3}

Final Answer:

The slope of the line perpendicular to the line connecting A and B is:
mperpendicular=73m_\text{perpendicular} = -\frac{7}{3}

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