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    Find the slope of the line which is perpendicular to the line connecting the points A(- 5, 3) and B(2, 6)
    Question

    Find the slope of the line which is perpendicular to the line connecting the points A(- 5, 3) and B(2, 6)

    A.

    49\frac{4}{9}

    B.

    35\frac{3}{5}​​

    C.

    87\frac{-8}{7}

    D.

    73\frac{-7}{3}

    Correct option is D

    Step 1: Find the slope of the line connecting points A and B

    The formula for the slope m between two points x1,y1x_1, y_1​ and x2,y2x_2, y_2​ is:
    m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}
    Substitute (x1,y1)(x_1, y_1)​ = (-5, 3) and (x2,y2)(x_2, y_2)​ = (2, 6):
    m=632(5)=37m = \frac{6 - 3}{2 - (-5)} = \frac{3}{7}

    Step 2: Find the slope of the perpendicular line.
    The slope of a line perpendicular to another is the negative reciprocal of the original slope. If the slope of the original line is m, the slope of the perpendicular line is:
    mperpendicular=1mm_\text{perpendicular} = -\frac{1}{m}

    Substitute m=37m = \frac{3}{7}
    mperpendicular=137=73m_\text{perpendicular} = -\frac{1}{\frac{3}{7}} = -\frac{7}{3}

    Final Answer:

    The slope of the line perpendicular to the line connecting A and B is:
    mperpendicular=73m_\text{perpendicular} = -\frac{7}{3}

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