Correct option is D
GIVEN:
GP series = 4, 8, 16, 32, ... 512.
FORMULA USED:
Tn = a×r(n-1)
where a = first term, r = common difference, n = number of terms
SOLUTION:
GP series = 4, 8, 16, 32, ... 512.
Tn = a×r(n-1)
=> 512 = 4 × 2(n - 1)
=> 128 = 2(n - 1)
=> 27 = 2(n - 1)
Now comparing powers we obtain;
=> n - 1 = 7
=> n = 8