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    Find the number of terms in the sequence 4, 8, 16, 32, ...512.
    Question

    Find the number of terms in the sequence 4, 8, 16, 32, ...512.

    A.

    7

    B.

    10

    C.

    9

    D.

    8

    Correct option is D

    GIVEN:
    GP series = 4, 8, 16, 32, ... 512.
    FORMULA USED:
    Tn = a×r(n-1) 

    where a = first term, r = common difference, n = number of terms
    SOLUTION:
    GP series = 4, 8, 16, 32, ... 512.
    Tn = a×r(n-1)
    => 512 = 4 × 2(n - 1)
    => 128 = 2(n - 1)
    => 27 = 2(n - 1)
    Now comparing powers we obtain;
    => n - 1 = 7
    => n = 8

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