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Find the number of 3 digit numbers that can be formed using the digit 0 , 1 , 4 , 5, 7 such that repetition of digits is not allowed?
Question

Find the number of 3 digit numbers that can be formed using the digit 0 , 1 , 4 , 5, 7 such that repetition of digits is not allowed?

A.

48

B.

120

C.

504

D.

720

Correct option is A

Given:
The digits available are 0, 1, 4, 5, 7.
The task is to form a 3-digit number such that repetition of digits is not allowed.
Concept Used:
A 3-digit number cannot start with 0.
Solution:
For the first digit, since it cannot be 0, we have the following choices: 1, 4, 5, 7 (4 choices).
For the second digit, we can choose any digit from the available set except the first digit (since repetition is not allowed), so we have 4 remaining choices.
For the third digit, we can choose any of the remaining digits except the first and second digits, so we have 3 choices.
4
4
3
Total number of 3-digit numbers = 4 × 4 × 3 = 48
So, the total number of 3-digit numbers that can be formed is 48.
Thus, the correct answer is (a).

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