Find the maximum number of children among whom 429 pencils and 715 pens can be equally distributed.

Correct option is A

Solution:

To find the maximum number of children, we need to find the greatest common divisor (HCF) of 429 and 715.
The HCF will give us the largest number by which both 429 and 715 can be divided.
First, find the prime factorization of both numbers:
​$$429 = 3 \times 11 \times 13$$​​
​$$715 = 5 \times 11 \times 13$$​​
The common factors between 429 and 715 are 11 and 13, so the GCD is:
​$$\text{HCF}(429, 715) = 11 \times 13 = 143$$​​
Therefore, the maximum number of children among whom 429 pencils and 715 pens can be equally distributed is 143.