Find the logic equation for the truth table given:

A	B	Y
0	0	0
1	0	1
0	1	1
1	1	0

Correct option is C

1. Function type: Truth table matches XOR (output 1 when inputs differ).
2. Minimal SOP: $$A \oplus B = \bar{A}B + A\bar{B}$$​ uses two product terms, each with two literals.
3. K-map view: Ones at cells (A, B) = (0, 1) and (1, 0) are isolated; each yields one implicant.
4. Symmetry: XOR is symmetric in A and B; swapping inputs doesn’t change Y.
5. Implementations: Two AND gates feeding an OR, plus two inverters; or a single XOR gate.
6. Uses: Parity checking, adders (sum bit), inequality tests, bit toggling.

Knowledge Booster

• Why (a) $$\bar{A}\bar{B}\cdot AB$$​ is wrong: The product contains contradictory literals ($$\bar{A}A=0, \bar{B}B=0$$​), so the whole term is always 0.
• Why (b) $$\bar{A}B\cdot A\bar{B}$$​ is wrong: Also contradictory when multiplied together; it evaluates to 0 for all inputs.
• Why (d) $$\bar{A}\bar{B}+AB$$​ is wrong: That’s XNOR (output 1 when inputs are equal), the complement of XOR, giving 1 for (0, 0) and (1, 1) instead of the required cases.