GIVEN:
The number = 588
SOLUTION:
Determine the prime factors of 588 we get,
588 = 2 × 2 × 7 × 7 × 3
Common factors = 2 × 7
Uncommon factor = 3
Now only 3 which is an uncommon factor that is not in pair. So the least number by which 588 be multiplied to get a perfect number is 3.
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is NOT a multiple of:
How many factors of are even?
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