Find the area under the curve y = $$3\text x^2$$ - 2x from x = 2 to x = 4.

Correct option is C

​$$\begin{aligned}&\text{The area } A \text{ under the curve from } x = 2 \text{ to } x = 4 \text{ is given by:} \\&\qquad A = \int_{2}^{4} (3x^2 - 2x) dx \\\\&\textbf{Compute the Antiderivative} \\&\text{Find the antiderivative of the integrand } 3x^2 - 2x: \\&\qquad \int (3x^2 - 2x) dx = x^3 - x^2 + C \\&\text{where } C \text{ is the constant of integration (which cancels out in definite integrals).} \\\\&\textbf{Evaluate the Definite Integral} \\&\text{Apply the Fundamental Theorem of Calculus:} \\&\qquad A = \left[ x^3 - x^2 \right]_{2}^{4} = (4^3 - 4^2) - (2^3 - 2^2) \\&\qquad \phantom{A} = (64 - 16) - (8 - 4) \\&\qquad \phantom{A} = 48 - 4 \\&\qquad \phantom{A} = 44\end{aligned}$$​​