Find one-third part of a number whose one-third part exceeds the one-fifth part by 6.
Given:
One-third part of a number exceeds its one-fifth part by 6.
Concept Used:
Let the number be x.
The equation formed based on the given condition is:
One-third part of the number = x/3
One-fifth part of the number = x/5
Solution:
According to the given condition,
5x - 3x = 90
2x = 90
x = 45
The number is 45.
One-third part of the number is: 45/3 = 15
English
100 Questions
100 Marks
90 Mins English English100 Questions100 Marks90 Mins English English100 Questions100 Marks90 Mins EnglishFind the square root of 0.000625 and express it as a fraction.
0.007 × 0.005 = ?
= ?
83 + (82 - 3) - 12 + 61 - 54 + 98 - 11 = ?
78 + 25 × 2 - (36 ÷ 3) + 44 - 17 + 11 = ?
45 + 68 - (25 + 17) + 96 × 2 - 48 = ?
There are 540 students in a school. One-third of them are girls. Three-fifth of the number of boys are players and one-fourth of the girls are players. Total number of players in the school is
44444444 ÷ 44 =
77 ÷ 0.007 =
Suggested Test Series
Suggested Test Series
Find the square root of 0.000625 and express it as a fraction.
0.007 × 0.005 = ?
= ?
83 + (82 - 3) - 12 + 61 - 54 + 98 - 11 = ?
78 + 25 × 2 - (36 ÷ 3) + 44 - 17 + 11 = ?
45 + 68 - (25 + 17) + 96 × 2 - 48 = ?
There are 540 students in a school. One-third of them are girls. Three-fifth of the number of boys are players and one-fourth of the girls are players. Total number of players in the school is
44444444 ÷ 44 =
77 ÷ 0.007 =
