arrow
arrow
arrow
​ Evaluate ∫x(x2−7)15dx. \text { Evaluate } \int x\left(x^2-7\right)^{15} d x \text {. } Evaluate ∫x(x2−7)15dx. ​​
Question

 Evaluate x(x27)15dx\text { Evaluate } \int x\left(x^2-7\right)^{15} d x \text {. }​​

A.

​​(x3+7)15+C(x^3+7)^{15}+C​​

B.

(x37)15+C(x^3-7)^{15}+C​​

C.

132(x27)16+C\frac{1}{32}(x^2-7)^{16}+C​​

D.

(x27)16+C(x^2-7)^{16}+C​​

Correct option is C

Let:u=x27Then, the derivative of u with respect to x is:dudx=2x=>du=2x dx=>x dx=du2Step 2: Rewrite the Integral in Terms of uSubstitute u and x dx into the integral:x(x27)15dx=u15du2=12u15 duStep 3: Integrate with Respect to uIntegrate u15:12u15 du=12u1616+C=u1632+CStep 4: Substitute Back for xReplace u with x27:u1632+C=(x27)1632+C\begin{aligned}&\text{Let:} \\&\quad u = x^2 - 7 \\[10pt]&\text{Then, the derivative of } u \text{ with respect to } x \text{ is:} \\&\quad \frac{du}{dx} = 2x \Rightarrow du = 2x \, dx \Rightarrow x \, dx = \frac{du}{2} \\[10pt]&\textbf{Step 2: Rewrite the Integral in Terms of } u \\&\text{Substitute } u \text{ and } x \, dx \text{ into the integral:} \\&\quad \int x(x^2 - 7)^{15} dx = \int u^{15} \cdot \frac{du}{2} = \frac{1}{2} \int u^{15} \, du \\[10pt]&\textbf{Step 3: Integrate with Respect to } u \\&\text{Integrate } u^{15}: \\&\quad \frac{1}{2} \int u^{15} \, du = \frac{1}{2} \cdot \frac{u^{16}}{16} + C = \frac{u^{16}}{32} + C \\[10pt]&\textbf{Step 4: Substitute Back for } x \\&\text{Replace } u \text{ with } x^2 - 7: \\&\quad \frac{u^{16}}{32} + C = \frac{(x^2 - 7)^{16}}{32} + C\end{aligned}​​

test-prime-package

Access ‘AAI JE ATC’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
354k+ students have already unlocked exclusive benefits with Test Prime!
test-prime-package

Access ‘AAI JE ATC’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
354k+ students have already unlocked exclusive benefits with Test Prime!
Our Plans
Monthsup-arrow