Energy produced in a power station is 2400 MWh per day. What is the maximum demand of the station if its load factor is 0.5?

Correct option is B

​$$\text{The load factor of a power station is defined as:} \\[8pt]\text{Load Factor} = \frac{\text{Average Load}}{\text{Maximum Demand}} \\[14pt]\textbf{Step 1: Find Average Load} \\[8pt]\text{Energy generated per day} = 2400 \text{ MWh} \\[10pt]\text{Average Load} = \frac{\text{Energy}}{\text{Time}} = \frac{2400 \text{ MWh}}{24 \text{ h}} = 100 \text{ MW} \\[16pt]\textbf{Step 2: Use Load Factor} \\[8pt]\textbf{Given:} \\[6pt]\text{Load Factor} = 0.5 \\[12pt]0.5 = \frac{100}{\text{Maximum Demand}} \\[10pt]\text{Maximum Demand} = \frac{100}{0.5} = 200 \text{ MW}$$​​