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    Deeksha travels in her car from City A to City B at a speed of 120 km/h, and while coming back by the same route from City B to City A she travels at
    Question

    Deeksha travels in her car from City A to City B at a speed of 120 km/h, and while coming back by the same route from City B to City A she travels at a speed of 130 km h . Find Deeksha’s average speed during the whole journey

    A.

    123.9 km/h

    B.

    122.8 km/h

    C.

    124.8 km/h

    D.

    125.0 km/h

    Correct option is C

    Given:

    Speed from City A to City B = 120 km/h

    Speed from City B to City A = 130 km/h 

    Formula Used : 

    Average speed=2×SpeedAB×SpeedBASpeedAB+SpeedBA\text{Average speed} = \frac{2 \times \text{Speed}_{A \to B} \times \text{Speed}_{B \to A}}{\text{Speed}_{A \to B} + \text{Speed}_{B \to A}} 

    Solution: 

    Average speed=2×120×130120+130\text{Average speed} = \frac{2 \times 120 \times 130}{120 + 130} 

    2×15600250\frac{2\times15600}{250} 

    31200250\frac{31200}{250} 

    312025\frac{3120}{25} 

    6245\frac{624}5 

    = 124.8 km/h

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