Consider the V-I graphs for wires of material A and material B as described below:
Material A: It is a straight line passing through origin and is inclined at 20^∘ to the current I axis.
Material B: It is a straight line passing through origin and is inclined at 60^∘ to the current I axis. Which of the following options is correct?

Correct Option : (C)  Both A and B follow Ohm's law.

The V-I graph relates voltage (V) and current ( I ) for a material.

 The slope of the  V - I  graph gives the resistance of the material:

​ The angles given are:
​Material A: 
​Material B:  
​
$$\theta$$_A = $$20^\circ$$​$$\theta$$_B = $$60^\circ$$

Formula used :     

R = $$\text{slope of the graph } = \tan(\theta)$$, 

Calculation of Resistance:
For Material A : 

$$R_A = \tan(20^\circ) \approx 0.364$$​

For Material B :

$$R_B = \tan(60^\circ) = \sqrt{3}\approx 1.732$$​      

Conclusion:
Material B has a higher resistance than Material A, as R_B > R_A . 
The graph for Material B is steeper than that of Material A, indicating greater resistance.

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