Recurrence RelationMultiply both sides of the series expansion f(z)(1−z−z2)=1:(n=0∑∞anzn)(1−z−z2)=1.Expand the product:n=0∑∞anzn−n=0∑∞anzn+1−n=0∑∞anzn+2=1.Reindex the second and third terms to align powers of zn:In the second term: replace n→n−1, giving n=1∑∞an−1zn,In the third term: replace n→n−2, giving n=2∑∞an−2zn.The equation becomes:a0+(a1−a0)z+n=2∑∞(an−an−1−an−2)zn=1.For this to hold for all powers of z, the coefficients must satisfy:a0=1,a1−a0=0⟹a1=a0=1,For n≥2:an=an−1+an−2.
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