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    Consider the following statements about magnetic field due to a current-carrying solenoid:(a) The magnetic field is uniform inside the solenoid.(b) On
    Question

    Consider the following statements about magnetic field due to a current-carrying solenoid:

    (a) The magnetic field is uniform inside the solenoid.

    (b) One end of the solenoid behaves like the north pole and the other like the south pole of a bar magnet.

    Which of the above statements is/are correct?

    A.

    (a) Only (a)

    B.

    (b) Both (a) and (b)

    C.

    Neither (a) nor (b)

    D.

    Only (b)

    Correct option is B

    Sol: The correct answer is (b) Both (a) and (b)

    A current-carrying solenoid is a cylindrical coil of wire that generates a magnetic field when an electric current passes through it

    ​Explanation:

    Statement (a): The magnetic field is uniform inside the solenoid

    • This is correct. The magnetic field inside a current-carrying solenoid is nearly uniform and parallel to its axis, making it similar to the field within a bar magnet.

    Statement (b): One end of the solenoid behaves like the north pole and the other like the south pole of a bar magnet

    This is also correct. A current-carrying solenoid creates a magnetic field that resembles the field of a bar magnet, with one end behaving like the north pole and the other as the south pole.

    ​Thus, both statements are correct.

    Information booster:

    Solenoid: A solenoid is a type of electromagnet created by winding a coil into a compact helix. It generates a controlled magnetic field when an electric current passes through it. This makes solenoids electromagnets because they rely on electric current to produce the magnetic field.

    • Magnetic Poles: A solenoid acts like a magnet with a north pole at one end and a south pole at the other.
    • Uniform Magnetic Field: Inside the solenoid, the magnetic field is always uniform and never zero.
    • Field Strength Formula: The magnetic field (B) inside the solenoid is given by the formula

    B = μoNI\mu_oNI

    μ0\mu_0 is the permeability of free space.

    N is the number of turns per unit length of the coil.

    II is the current flowing through the solenoid.

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