Correct option is C
Correct Answer: (c)
Explanation:
Hexokinase catalyses the transfer of a phosphoryl group from ATP to glucose forming glucose-6-phosphate. This is the first phosphoryl-transfer step of glycolysis.
Information Booster:
Hexokinase uses ATP as phosphate donor and converts glucose → glucose-6-phosphate.
This step is irreversible under physiological conditions.
Phosphoglycerate mutase only relocates phosphate within the same molecule.
Enolase removes water, not phosphate.
Aldolase breaks fructose-1,6-bisphosphate into two triose phosphates.
Additional Information (Incorrect Options):
(a) Mutase catalyses internal phosphate shifts (isomerization).
(b) Enolase catalyses dehydration.
(d) Aldolase splits C–C bond, not phosphoryl transfer.