By interchanging the given two signs and numbers which of the following equation will be not correct?
× and –, 8 and 4
I. 4 + 3× 8 – 2 ÷ 1 = 3
II. 8 × 2 – 4 + 6 ÷ 2 = 11

Interchange × and –, 8 and 4

​$$\begin{array}{|c|c|} \hline\textbf{Operation preference wise} & \textbf{Symbol} \\\hline\text{Brackets} &[], {}, () \\ \hline \text{Orders, of} & (power), √ (root) , of \\ \hline \text{Division}& ÷ \\ \hline \text{Multiplication} & × \\\hline \text{Addition} &+ \\ \hline \text{Subtraction} & - \\\hline\end{array}$$

So, Only II is incorrect.

Thus, the correct option is: (b)