By Interchanging the given two numbers which of the following equation will be NOT correct?
3 and 5

Correct option is D

Given: By Interchanging 3 and 5
Bodmas table-
​$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}$$​​
From the given options –
(a) 5 – 3 + 6 = 4 after interchanging the digit 3 and 5 we get following equation -
3 – 5 + 6 = 4
9 – 5 = 4
4 = 4
(b) 7 × 4 – 5 + 3 = 30 after interchanging the digit 3 and 5 we get following equation -
7 × 4 – 3 + 5 = 30
28 – 3 + 5 = 30
33 – 3 = 30
30 = 30
(c) 5 + 3 × 2 – 1 = 12 after interchanging the digit 3 and 5 we get following equation -
3 + 5 × 2 – 1 = 12
3 + 10 – 1 = 12
13 – 1 = 12
12 = 12
(d) 5 × 4 + 3 – 2 = 18 after interchanging the digit 3 and 5 we get following equation -
3 × 4 + 5 – 2 = 18
12 + 5 – 2 = 18
17 – 2 = 18
16 ≠ 18
Thus, the correct answer is (d).