By Interchanging the given two numbers (not digits) which of the following equation will be NOT correct?
5 and 8

Correct option is C

Let's check each option after interchanging 5 and 8
Bodmas table
$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division& ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}$$​(a) 5 × 7 + 8 – 3 = 58 After interchanging the 5 and 8 we get following equation-
8 × 7 + 5 – 3 = 58
56 + 5 – 3 = 58
61 – 3 = 58
58 = 58
b) 5 + 8 × 3 – 9 = 14 After interchanging the 5 and 8 we get following equation-
8 + 5 × 3 – 9 = 14
8 + 15 – 9 = 14
23 – 9 = 14
14 = 14
(c) 8 – 5 × 2 + 6 = -3 After interchanging the 5 and 8 we get following equation-
5 – 8 × 2 + 6 = -3
5 – 16 + 6 = -3
11 – 16 = -3
-5 ≠ -3
Thus correct option is (c).