Correct option is D
Given:
JM – IL, NQ – MP, FI – EH, NT – JK

Logic:
In each pair, the second cluster is formed by subtracting 1 alphabetically from each letter of the first cluster.
Explanation (applied left to right):
J − 1 = I, M − 1 = L → IL
N − 1 = M, Q − 1 = P → MP
F − 1 = E, I − 1 = H → EH
N − 1 = M, T − 1 = S → JK (does not follow the pattern)
Final Answer:
NT – JK
Final Correct Option:
(d) NT – JK