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    At z = 0, the function 1/(z-sinz ) of a complex variable z has
    Question

    At z = 0, the function 1/(z-sinz ) of a complex variable z has

    A.

    no singularity

    B.

    a simple pole

    C.

    a pole of order 2

    D.

    a pole of order 3

    Correct option is D

    Concept:
    A pole of an analytic function is a point at which the function goes to infinity. It is also known as the singularity of the function.

    For example, if the function is given as : f(x)=1/x−2.  At x = 2, the function will become infinite. So,  x = 2  is the singularity point of the function or the pole of the function.
    Solution:
    The sine function can be written as :

    Substituting the above equation in the function:


    Now, this function will become infinity at point  z=0. 
    But the power of  is  3, which states the order of the pole.

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