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    An object is placed at a distance of 10 cm in from of a concave mirror. Its image is formed ill a distance at 15 cm on the same side. The focal length
    Question

    An object is placed at a distance of 10 cm in from of a concave mirror. Its image is formed ill a distance at 15 cm on the same side. The focal length of the mirror is:


    A.

    30 cm


    B.

    6 cm


    C.

    -6 cm


    D.

    -30 cm

    Correct option is C

    Correct Answer: C - -6 cm

    Explanation:

    The formula for a spherical mirror is:

    1f=1u+1v\frac{1}{f} = \frac{1}{u} + \frac{1}{v}​​

    Where:

    • f = focal length
    • u = object distance (negative for concave mirror as it is in front of the mirror)
    • v = image distance (negative for real image as it is on the same side as the object)

    Given:

    • u=−10 cm (object distance)
    • v=−15 cm (image distance)

    Substitute the values into the formula:

    1f=1u +1v 1f=110+115 1f=110115\frac{1}{f} = \frac{1}{u}\ + \frac{1}{v}\\ \ \\\frac{1}{f} = \frac{1}{-10} + \frac{1}{-15}\\ \ \\ \frac{1}{f} = -\frac{1}{10} - \frac{1}{15}​​

    Find the common denominator:

    1f=(330+230)  1f=530\frac{1}{f} = -\left(\frac{3}{30} + \frac{2}{30}\right)\ \\ \ \\ \frac{1}{f} = -\frac{5}{30}​​

    Simplify:

    f=−6 cm

    Information Booster:

    •  A negative focal length indicates the mirror is concave.
    •  For concave mirrors, a real and inverted image forms on the same side as the object when the object is placed beyond the focal point.
    •  The formula applies universally to concave and convex mirrors, with appropriate sign conventions.
    • The focal length is half the radius of curvature (f=R/2).
      ● In this case, the mirror forms a real image, which is always inverted for concave mirrors.

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