An aeroplane travels distances 1320 km, 1760 km and 2095 km at the rate of 528 km/h, 352 km/h and 419 km/h, respectively. Find the average speed (in km/h) of the aeroplane.

Correct option is D

Given:
Distances = 1320 km, 1760 km, 2095 km
Speeds = 528 km/h, 352 km/h, 419 km/h
Formula Used:
Average Speed = $$\frac{\text{Total Distance}}{\text{Total Time}}$$​​
Solution:
Total Distance = 1320 + 1760 + 2095 = 5175 km
​$$\text{Total Time} = \frac{1320}{528} + \frac{1760}{352} + \frac{2095}{419} = 2.5 + 5 + 5 = 12.5 \text{ hours}$$​

Average Speed =  $$\frac{5175}{12.5} = 414 \text{ km/h}$$​​