After interchanging which two numbers, the value of the given equation will be '33'?

​$$8÷2-5+6×7$$​​​​

Given: ​$$8÷2-5+6×7$$

Given equation is solve by BODMAS rule.

$$\begin{array}{|c|c|} \hline\textbf{Operation preference wise} & \textbf{Symbol} \\\hline\text{Brackets} &[],{}, () \\ \hline \text{Orders, of} & (power), √ (root) , of \\ \hline \text{Division}& ÷ \\ \hline \text{Multiplication} & × \\ \hline \text{Addition} & + \\ \hline \text{Subtraction} & - \\\hline\end{array}$$​​

Now, we check each options.

Option (a): 7 and 5

New equation: 8 $$\div$$ 2 - 7 + 6 $$\times$$ 5

= 4 - 7 + 6 $$\times$$​ 5

= 4 - 7 + 30

= 34 - 7

= 27

Option (b): 5 and 6

New equation: 8 $$\div$$​ 2 - 6 + 5 $$\times$$​ 7

= 4 - 6 + 5 $$\times$$​​ 7

= 4 - 6 + 35

= 39 - 6

= 33

Option (c): 6 and 8

New equation: 6 $$\div$$ 2 - 5 + 8 $$\times$$​​ 7

= 3 - 5 + 8 $$\times$$​​​ 7

= 3 - 5 + 56

= 59 - 5

= 54

Option (d): 8 and 5

New equation: 5 $$\div$$ 2 - 8 + 6 $$\times$$​ 7

5 is not divisible by 2.

Thus, correct option is (b).