After interchanging ‘÷’ and '×’, and interchanging ‘2’ and 1, which of the following equations is correct?

Correct option is C

Given: 3 ÷ 1 + 3 × 3 – 2 = 7
After interchanging ‘÷’ and '×’, and interchanging ‘2’ and 1 in the given options-
From option (a) 3 ÷ 1 + 3 × 3 – 2 = 5
After interchanging ‘÷’ and '×’, and interchanging ‘2’ and 1 we get following equation-
3 × 2 + 3 ÷ 3 – 1 = 5
3 × 2 + 1 – 1 = 5
6 + 1 – 1 = 5
7 – 1 = 5
6 ≠ 5
(b) 3 ÷ 1 + 3 × 3 – 2 = 8
After interchanging ‘÷’ and '×’, and interchanging ‘2’ and 1 we get following equation-
3 × 2 + 3 ÷ 3 – 1 = 8
3 × 2 + 1 – 1 = 8
3 × 2 + 1 – 1 = 8
6 + 1 – 1 = 8
7 – 1 = 8
6 ≠ 8
(c) 3 ÷ 1 + 3 × 3 – 2 = 6
After interchanging ‘÷’ and '×’, and interchanging ‘2’ and 1 we get following equation-
3 × 2 + 3 ÷ 3 – 1 = 6
3 × 2 + 1 – 1 = 6
3 × 2 + 1 – 1 = 6
6 + 1 – 1 = 6
7 – 1 = 6
6 = 6
(d) 3 ÷ 1 + 3 × 3 – 2 = 7
After interchanging ‘÷’ and '×’, and interchanging ‘2’ and 1 we get following equation-
3 × 2 + 3 ÷ 3 – 1 = 7
3 × 2 + 1 – 1 = 7
3 × 2 + 1 – 1 = 7
6 + 1 – 1 = 7
7 – 1 = 7
6 ≠ 7
Thus, the correct answer is (c).