Correct option is C
Conditions:
The value is less than 8 but higher than 3.
- This implies: 3<Value<83 < \text{Value} < 83<Value<8.
The value is higher than 6 but less than 10.
- This implies: 6<Value<106 < \text{Value} < 106<Value<10.
Finding the Common Range:
The number must satisfy both conditions:
- From Condition 1: 3<Value<83 < \text{Value} < 83<Value<8.
- From Condition 2: 6<Value<106 < \text{Value} < 106<Value<10.
The overlap of these two ranges is:
6<Value<86 < \text{Value} < 86<Value<8
Possible Number:
The only integer in this range is 7.