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    A trip to a destination is made in the following way:a)550 km by train at an average speed of 55 km/hb)4500 km by plane at an average speed of 500 km/
    Question

    A trip to a destination is made in the following way:

    a)550 km by train at an average speed of 55 km/h

    b)4500 km by plane at an average speed of 500 km/h

    c)400 km by boat at an average speed of 25 km/h

    d)55 km by auto at an average speed of 35 km/h

    What is the average speed for the entire journey?

    A.

    3300 km/hr

    B.

    9600 km/hr

    C.

    1216425km/hr121\frac{64}{25} km/hr​​

    D.

    150135256km/hr150\frac{135}{256} km /hr​​

    Correct option is D

    Given:

    550 km by train at an average speed of 55 km/h

    4500 km by plane at an average speed of 500 km/h

    400 km by boat at an average speed of 25 km/h

    55 km by auto at an average speed of 35 km/h

    Formula Used:

    Time = DistanceSpeed \ \frac{Distance}{Speed}​​

    Solution:

    Time taken by train at 55km/hr = 55055=10hrs \frac{550}{55} = 10hrs​​

    Time taken by plane at 500km/hr =  4500500=9hrs\frac{4500}{500} = 9hrs​​

    Time taken by boat at 25km/hr =40025=16hrs \frac{400}{25} = 16hrs​​

    Time taken by auto at 35km/hr = 5535=117hrs \frac{55}{35} = \frac{11}{7}hrs​​

    Total distance =550 + 4500 + 400 + 55 = 5505

    Total time taken =10+9+16+117=70+63+112+117=2567 hrs10+9+16+\frac{11}{7} = \frac{70+63+112+11}{7}=\frac{256}{7}\ hrs​​

    Average speed =55052567=5505×7256 \frac{5505}{\frac{256}{7}} =\frac{5505 \times7}{256}

    =38,535256=150135256 km/hr=\frac{38,535}{256} = 150\frac{135}{256} \ km/hr​​

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