A train passes a station platform in 69 seconds and a man standing on the platform in 53 seconds. If the speed of the train is 29 m/s, what is the length of the platform (in meters)?

Correct option is A

Ans. (a)
Sol. Let the length of the train be L and the length of the platform be P.
· The train passes the man in 53 seconds, so: Speed = Distance / Time 29 = L / 53 Therefore, L = 29 × 53 = 1537 meters.
· The train passes the entire platform in 69 seconds: Speed = Distance / Time 29 = (L + P) / 69 So, 29 × 69 = L + P 2001 = 1537 + P, thus P = 2001 - 1537 = 464 meters.