A tank can be filled by two taps A and B in 8 hours and 10 hours, respectively. The full tank can be emptied by a third tap in 12 hours. If all the taps are turned on at the same time, in how much time (in approximate number of hours) will the empty tank be filled completely?
Given:
Tap A fill the tank in 8 hours
Tap B fill the tank in 10 hours
Tap C empty the tank in 12 hours
Formula Used:
Solution:
LCM of 8, 10, 12 = 120
Total capacity of tank = 120 units
Efficiency of Tap A = = 15 units
Efficiency of Tap B = = 12 units
Efficiency of Tap C = = 10 units
Effective of these three tanks together = (15 + 12 – 10) = 17 unit
Time taken to fill the tank when they all opened simultaneously = = 7.0588 ≈ 7 hours
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100 Questions
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