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    A sum of ₹30,000 is invested on compound interest of 712\frac{1}{2}21​​% p.a. What is the sum at the end of the second year?
    Question

    A sum of ₹30,000 is invested on compound interest of 712\frac{1}{2}​% p.a. What is the sum at the end of the second year?

    A.

    ₹34,658.75

    B.

    ₹34,658

    C.

    ₹34,668

    D.

    ₹34,668.75

    Correct option is D

    Given:

    Principal amount = ₹30,000

    Rate of interest = 712%\frac{1}{2} \%​ per annum = 7.5 % per annum

    The interest is compounded annually.

    Formula Used:
    The formula for compound interest is:

    A =P(1+r100)t P \left(1 + \frac{r}{100}\right)^t

    Where:

    A is the amount after t years.

    P is the principal.

    r is the rate of interest.

    t is the number of years.

    Solution:

    A= 30000(1+7.5100)200 \left(1 + \frac{7.5}{100}\right)^2​ = 30000(1+0.075)20 \left(1 + 0.075\right)^2 ​= 30000×(1.075)20 \times (1.075)^2

    =30000×1.155625=34668.75000 \times 1.155625 = 34668.75

    Thus, the sum at the end of the second year is ₹34,668.75.

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