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A sphere of radius 14 cm is cut along three diametrical planes to form 6 equal parts. What would be the total surface area (in cm2) of all the new pie
Question

A sphere of radius 14 cm is cut along three diametrical planes to form 6 equal parts. What would be the total surface area (in cm2) of all the new pieces so obtained? (Take π = 22/7)

A.

7392

B.

4312

C.

6160

D.

5544

Correct option is C

Given:
Radius of the sphere = 14 cm
The sphere is cut into 6 equal parts along three diametrical planes.
Formula Used:
Surface area of a sphere = 4πr24\pi r^2​​
Area of a circle = πr2 \pi r^2​​
Solution:
When a sphere is cut along a diametrical plane, two new circular surfaces are exposed.
Since the sphere is cut along three diametrical planes, there are 3 cuts in total.
Each cut exposes 2 circular surfaces, so 3 cuts expose 3 × 2 = 6 full circular surfaces.
Total newly exposed area = 6πr2 6\pi r^2​​
Original spherical surface area = 4πr24\pi r^2​​
Total surface area of all new pieces =  4πr2+6πr2=10πr24\pi r^2 + 6\pi r^2 = 10\pi r^2​​
Substitute the values of  π\pi​ and r:
Total surface area = 10×227×14210 × \frac{22}{7} × 14^2​​

Total surface area = 10×227×19610 × \frac{22}{7} × 196

Total surface area = 10 × 22 × 28

Total surface area = 220 × 28 = 6160 cm2
Final Answer
So the correct answer is (c)

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