A shunt generator running at 1000 RPM has generated EMF of 100 V. If the speed increases to 1200 RPM, then the generated EMF will be-

Correct option is A

​$$N_1 = 100 \, \text{rpm}, \quad N_2 = 1200 \, \text{rpm}$$

$$E_{b1} = 100 \, \text{volt}, \quad E_{b2} = ?$$

$$N \propto \frac{E_b}{\phi}$$

$$\frac{N_1}{N_2} = \frac{E_{b1}}{E_{b2}}$$

$$\frac{1000}{1200} = \frac{100}{E_{b2}}$$

$$E_{b2} = \frac{100 \times 1200}{1000} = 120 \, \text{V}$$​​​​​​​